(2n^3+6n^2+4n)/2n

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Solution for (2n^3+6n^2+4n)/2n equation: 


n in (-oo:+oo)

n*((2*n^3+6*n^2+4*n)/2) = 0

(n*(2*n^3+6*n^2+4*n))/2 = 0

2*n^3+6*n^2+4*n = 0

2*n*(n^2+3*n+2) = 0

n^2+3*n+2 = 0

DELTA = 3^2-(1*2*4)

DELTA = 1

DELTA > 0

n = (1^(1/2)-3)/(1*2) or n = (-1^(1/2)-3)/(1*2)

n = -1 or n = -2

2*n*(n+2)*(n+1) = 0

(2*n*n*(n+2)*(n+1))/2 = 0

( 2*n )

2*n = 0 // : 2

n = 0

( n+1 )

n+1 = 0 // - 1

n = -1

( n+2 )

n+2 = 0 // - 2

n = -2

( n )

n = 0

n in { 0, -1, -2, 0 }

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